Y=105t-16t^2

Solution for Y=105t-16t^2 equation:

=105Y-16Y^2

We move all terms to the left:

-(105Y-16Y^2)=0

We get rid of parentheses

16Y^2-105Y=0

a = 16; b = -105; c = 0;
Δ = b2-4ac
Δ = -1052-4·16·0
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-105}{2*16}=\frac{0}{32}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+105}{2*16}=\frac{210}{32}
=6+9/16
$